document.write( "Question 914116: 3,6/7,9/17,12/31,15/49,18/71 is my sequence what are the next 2 numbers in the sequence \n" ); document.write( "
Algebra.Com's Answer #554905 by KMST(5328)\"\" \"About 
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21/97 and 24/127
\n" ); document.write( "Numerators increase by 3
\n" ); document.write( "3 6 9 12 15 18 21 24 ...
\n" ); document.write( "The difference from one denominator to the next changes.
\n" ); document.write( "It starts with 6 and increases by 4 each time.
\n" ); document.write( "The first number is 3/1; the denominator is 1.
\n" ); document.write( "The second denominator is 6 more:
\n" ); document.write( "1+6=7,
\n" ); document.write( "and the second number is 6/7.
\n" ); document.write( "The third denominator is
\n" ); document.write( "6+4=10 more than the second:
\n" ); document.write( "7+10=17.
\n" ); document.write( "So the third number is 9/17.
\n" ); document.write( "To get the next denominator, you have to add 10+4=14, to get 17+14=31.
\n" ); document.write( "With that denominator, you get 12/31.
\n" ); document.write( "Next, you add 14+4=18 to get 31+18=49, for 15/49.
\n" ); document.write( "Then, you add 18+4=22 to get 49+22=71, for 18/71.
\n" ); document.write( "Then you add 22+4=26 to get 71+26=97, for 21/97.
\n" ); document.write( "Then you add 26+4=30 to get 97+30=127 for 24/127. \n" ); document.write( "
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