document.write( "Question 914107: The duration of phone calls to a Calling Centre is normally distributed with a mean of
\n" ); document.write( "seven minutes and a standard deviation of two minutes. Calculate the probability that a
\n" ); document.write( "phone call to the Calling Centre last for between 5 to 10 minutes.
\n" ); document.write( "(b) A recent survey found that 56% of mobile phone users, between the ages of 18 to 34,
\n" ); document.write( "had a smartphone. Suppose a random sample of 100 mobile phone users were selected.
\n" ); document.write( "What is the probability that less than 50 of them have a smartphone?
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Algebra.Com's Answer #554870 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
\"z+=blue+%28x+-+mu%29%2Fblue%28sigma%29\" mean = 7, sd = 2
\n" ); document.write( "P( 5 < x < 10) = normalcdf(-100, 3/2) - normalcdf(-100, -1) = .9332 - .1587 = .7745 0r 77.45%
\n" ); document.write( "0r may Use
\n" ); document.write( "P( 5 < x < 10) = normalcdf(-1, 3/2)
\n" ); document.write( "P( 5 < x < 10) Area between the green lines (z = -1 and z = 1.5)
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\n" ); document.write( "..........
\n" ); document.write( " \"z+=blue+%28x+-+mu%29%2Fblue%28.56%2A.44%2Fsqrt%28100%29%29%29\"
\n" ); document.write( "b) P( x < .50) = normacdf(-100, -1.2087) = .1134 0r 11.34%
\n" ); document.write( "\"z+=blue+%28.50+-+.56%29%2Fsqrt%28.56%2A.44%2F%28100%29%29\" = -1.2087
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