document.write( "Question 914040: The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #554869 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle?
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\n" ); document.write( "Let width of rectangle be W
\n" ); document.write( "Then length = 4W
\n" ); document.write( "Area of rectangle: W(4W), or \"4W%5E2\"
\n" ); document.write( "Perimeter of rectangle: 2(W + 4W), or 2(5W), or 10W
\n" ); document.write( "Therefore, we get: \"4W%5E2+=+2%2810W%29\"
\n" ); document.write( "\"4W%5E2+=+20W\"
\n" ); document.write( "\"4W%5E2+-+20W+=+0\"
\n" ); document.write( "4W(W – 5) = 0
\n" ); document.write( "W – 5 = 0 OR 4W = 0
\n" ); document.write( "W, or width = \"highlight_green%285%29\" OR W = 0 (ignore)
\n" ); document.write( "Length: 4(5), or \"highlight_green%2820%29\" units of length \n" ); document.write( "
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