document.write( "Question 914044: If b+c-a/a, c+a-b/b, a+b-c/c are in A.P.\r
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document.write( "Prove that 1/a,1/b,1/c are also in A.P \n" );
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Algebra.Com's Answer #554851 by mananth(16946)![]() ![]() You can put this solution on YOUR website! b+c-a/a, c+a-b/b, a+b-c/c in AP\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ac-bc = ab-ac\r \n" ); document.write( "\n" ); document.write( "/abc\r \n" ); document.write( "\n" ); document.write( "1/b -1/a = 1/c-1/b\r \n" ); document.write( "\n" ); document.write( "Hence they are in AP\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |