document.write( "Question 914040: The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #554838 by Lenzky(18)\"\" \"About 
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\"x\" - Length
\n" ); document.write( "\"x%2F4\" - Wide\r
\n" ); document.write( "\n" ); document.write( "Perimeter
\n" ); document.write( "\"2x+%2B+2%28x%2F4%29+=+2x+%2B+x%2F2\" \r
\n" ); document.write( "\n" ); document.write( "Area
\n" ); document.write( "\"%28x%29%28x%2F4%29+=+x%5E2%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4+=+2%282x+%2B+x%2F2%29\"
\n" ); document.write( "\"x%5E2%2F4+=+4x+%2B+x\" times both side by 4
\n" ); document.write( "\"x%5E2+=+16x+%2B+4x\"
\n" ); document.write( "\"x%5E2+=+20x\"
\n" ); document.write( "\"x%5E2+-+20x+=+0\"
\n" ); document.write( "\"x%28x-20%29+=+0\"
\n" ); document.write( "\"x+=+0\"&\"x+=+20\"\r
\n" ); document.write( "\n" ); document.write( "Checking:
\n" ); document.write( "Length: \"X+=+20\"
\n" ); document.write( "Wide: \"x%2F4+=+20%2F4+=+5\" \r
\n" ); document.write( "\n" ); document.write( "P= 2L + 2W
\n" ); document.write( "P= 2(20) + 2(5)
\n" ); document.write( "P= 40 + 10
\n" ); document.write( "P= 50\r
\n" ); document.write( "\n" ); document.write( "A= LW
\n" ); document.write( "A= 20 x 5
\n" ); document.write( "A= 100\r
\n" ); document.write( "\n" ); document.write( "2P = A
\n" ); document.write( "2(50) = 100
\n" ); document.write( "100 = 100
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