document.write( "Question 914040: The width of a rectangle is 1/4 of the length. The area is twice the perimeter. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #554838 by Lenzky(18)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Area \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Checking: \n" ); document.write( "Length: \n" ); document.write( "Wide: \n" ); document.write( "\n" ); document.write( "P= 2L + 2W \n" ); document.write( "P= 2(20) + 2(5) \n" ); document.write( "P= 40 + 10 \n" ); document.write( "P= 50\r \n" ); document.write( "\n" ); document.write( "A= LW \n" ); document.write( "A= 20 x 5 \n" ); document.write( "A= 100\r \n" ); document.write( "\n" ); document.write( "2P = A \n" ); document.write( "2(50) = 100 \n" ); document.write( "100 = 100 \n" ); document.write( " \n" ); document.write( " |