document.write( "Question 913981: Please help me solve this problem:\r
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document.write( "The radiator in a car is filled with a solution of 70 per cent antifreeze and 30 per cent water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50 per cent antifreeze. If the capacity of the raditor is 3.6 liters, how much coolant (in liters) must be drained and replaced with pure water to reduce the antifreeze concentration to 50 per cent? \n" );
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Algebra.Com's Answer #554823 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "originally in radiator \n" ); document.write( "--------------- \n" ); document.write( "Note that \n" ); document.write( "replaced with \n" ); document.write( "radiator ends up with \n" ); document.write( "--------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "1.029 liters of coolant must be drained \n" ); document.write( "off and replaces with water \n" ); document.write( "-------------------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "re-filling with pure water \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK \n" ); document.write( " \n" ); document.write( " |