document.write( "Question 913957: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "Train A leaves a station traveling at 80 kilometers per hour. Two hours later, train B leaves the same station traveling in the same direction at 100 kilometers per hour. How long does it take train B to catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #554820 by mananth(16946)\"\" \"About 
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Train A speed= 80 km/h , starts at
\n" ); document.write( "Train B speed= 100 km/h starts at
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\n" ); document.write( "Time difference between the starting of the two= 2.00 hours
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\n" ); document.write( "Time taken by Train A = X / 80
\n" ); document.write( "Time taken by Train B = X / 100
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\n" ); document.write( "X / 80 - X / 100 = 2
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\n" ); document.write( "LCD - 90
\n" ); document.write( "Multiply equation by 90 90
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\n" ); document.write( "1.13 x - 0.9 x = 180
\n" ); document.write( "0.23 x = 180
\n" ); document.write( "/ 0.23
\n" ); document.write( "x= 800 km
\n" ); document.write( "Train B speed= 100 km/h
\n" ); document.write( "Distance = 800 miles
\n" ); document.write( "Time taken = 800 / 100
\n" ); document.write( "Time taken = 8 hours
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