document.write( "Question 913960: Please help me solve this problem:\r
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document.write( "A motorboat can go 14 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same 14 miles. Find the speed of the boat. \n" );
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Algebra.Com's Answer #554819 by mananth(16946)![]() ![]() You can put this solution on YOUR website! boat speed =x mph \n" ); document.write( "current speed =y mph \n" ); document.write( "against current 0.5 hours \n" ); document.write( "with current 1/ 3 hours \n" ); document.write( " \n" ); document.write( "Distance with current 14 miles distance against current 14 \n" ); document.write( "t=d/r against current (x-y) \n" ); document.write( "14.00 / ( x - y )= 0.50 \n" ); document.write( " \n" ); document.write( "0.50 x - -0.50 y = 14.00 ....................1 \n" ); document.write( "with current (x+y) \n" ); document.write( "14.00 / ( x + y )= 0.33 \n" ); document.write( "0.33 ( x + y ) = 14.00 \n" ); document.write( "0.33 x + 0.33 y = 14.00 ...............2 \n" ); document.write( "Multiply (1) by 0.33 \n" ); document.write( "Multiply (2) by 0.50 \n" ); document.write( "we get 2.00 \n" ); document.write( "0.17 x + -0.17 y = 4.62 \n" ); document.write( "0.17 x + 0.17 y = 7.00 \n" ); document.write( "0.33 x = 11.62 \n" ); document.write( "/ 0.33 \n" ); document.write( "x = 35.04 mph \n" ); document.write( " \n" ); document.write( " |