document.write( "Question 913960: Please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "A motorboat can go 14 miles downstream on a river in 20 minutes. It takes 30 minutes for this boat to go back upstream the same 14 miles. Find the speed of the boat.
\n" ); document.write( "

Algebra.Com's Answer #554819 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 0.5 hours
\n" ); document.write( "with current 1/ 3 hours
\n" ); document.write( "
\n" ); document.write( "Distance with current 14 miles distance against current 14
\n" ); document.write( "t=d/r against current (x-y)
\n" ); document.write( "14.00 / ( x - y )= 0.50
\n" ); document.write( "
\n" ); document.write( "0.50 x - -0.50 y = 14.00 ....................1
\n" ); document.write( "with current (x+y)
\n" ); document.write( "14.00 / ( x + y )= 0.33
\n" ); document.write( "0.33 ( x + y ) = 14.00
\n" ); document.write( "0.33 x + 0.33 y = 14.00 ...............2
\n" ); document.write( "Multiply (1) by 0.33
\n" ); document.write( "Multiply (2) by 0.50
\n" ); document.write( "we get 2.00
\n" ); document.write( "0.17 x + -0.17 y = 4.62
\n" ); document.write( "0.17 x + 0.17 y = 7.00
\n" ); document.write( "0.33 x = 11.62
\n" ); document.write( "/ 0.33
\n" ); document.write( "x = 35.04 mph
\n" ); document.write( "
\n" ); document.write( "
\n" );