document.write( "Question 913963: Please help me answer this question:\r
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document.write( "A plane flies 900 miles with a tail wind in 3 hours. It takes the same plane 5 hours to fly the 900 miles when flying against the wind. What is the plane's speed in still air? \n" );
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Algebra.Com's Answer #554805 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! r*t=d \n" ); document.write( "with the wind \n" ); document.write( "(r+w)*3=900 \n" ); document.write( "(r+w)=900/3 \n" ); document.write( "r+w=300 \n" ); document.write( "against the wind \n" ); document.write( "(r-w)*5=900 \n" ); document.write( "(r-w)=900/5\r \n" ); document.write( "\n" ); document.write( "r-w=180 \n" ); document.write( "r+w=300 \n" ); document.write( "add \n" ); document.write( "r+r=300+180 \n" ); document.write( "2r=480 \n" ); document.write( "r=240 mph rate of plane in still air\r \n" ); document.write( "\n" ); document.write( "240-w=180 \n" ); document.write( "w=240-180 \n" ); document.write( "w=60 mph wind \n" ); document.write( "check \n" ); document.write( "(240+60)*3=900 \n" ); document.write( "300*3=900 \n" ); document.write( "900=900 \n" ); document.write( "ok \n" ); document.write( "(r-w)*5=900 \n" ); document.write( "(240-60)*5=900 \n" ); document.write( "180*5=900 \n" ); document.write( "900=900 \n" ); document.write( "ok \n" ); document.write( "codedrtdtt \n" ); document.write( " \n" ); document.write( " |