document.write( "Question 913963: Please help me answer this question:\r
\n" ); document.write( "\n" ); document.write( "A plane flies 900 miles with a tail wind in 3 hours. It takes the same plane 5 hours to fly the 900 miles when flying against the wind. What is the plane's speed in still air?
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Algebra.Com's Answer #554805 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
r*t=d
\n" ); document.write( "with the wind
\n" ); document.write( "(r+w)*3=900
\n" ); document.write( "(r+w)=900/3
\n" ); document.write( "r+w=300
\n" ); document.write( "against the wind
\n" ); document.write( "(r-w)*5=900
\n" ); document.write( "(r-w)=900/5\r
\n" ); document.write( "\n" ); document.write( "r-w=180
\n" ); document.write( "r+w=300
\n" ); document.write( "add
\n" ); document.write( "r+r=300+180
\n" ); document.write( "2r=480
\n" ); document.write( "r=240 mph rate of plane in still air\r
\n" ); document.write( "\n" ); document.write( "240-w=180
\n" ); document.write( "w=240-180
\n" ); document.write( "w=60 mph wind
\n" ); document.write( "check
\n" ); document.write( "(240+60)*3=900
\n" ); document.write( "300*3=900
\n" ); document.write( "900=900
\n" ); document.write( "ok
\n" ); document.write( "(r-w)*5=900
\n" ); document.write( "(240-60)*5=900
\n" ); document.write( "180*5=900
\n" ); document.write( "900=900
\n" ); document.write( "ok
\n" ); document.write( "codedrtdtt
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