document.write( "Question 10369: the height in feet for a ball thrown upward at 48 feet persecond is given by s(t)=-16t2+48t, where t is the time in seconds after the ball is tossed. what is the maximum height that the ball will reach?\r
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document.write( "Please help me with this problem... \n" );
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Algebra.Com's Answer #5548 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "The maximum height of the thrown object will be at the vertex (the maximumum value) (h, t) of the parabola.\r \n" ); document.write( "\n" ); document.write( "The t-coordinate (equivalent to the x-coordnate) of the vertex (this is the time at which the object reaches its maximum height) is given by \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "To find the value of the maximum height at t = 3/2 secs, substitute t = 3/2 into the original quadratic equation and solve for h.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "As a check, you could take the first derivative of the quadratic equation and set it to zero to find the value of t at the maximum height. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |