document.write( "Question 913776: If 60% of all households own VCRs, what is the probability that 11 households are selected at random, more than 7 will own VCRs? With explanation please. Thanks \n" ); document.write( "
Algebra.Com's Answer #554715 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! p(owns VCR) = .60, n = 11 \n" ); document.write( "P(x > 7) =1- binomcdf(11, .60, 7) = 1 - .7037 = .2963 Using TI \n" ); document.write( "0r \n" ); document.write( "By hand... \n" ); document.write( "Using \n" ); document.write( "p and q are the probabilities of success and failure respectively. \n" ); document.write( "In this case p = .6 & q are = .4, n = 11 \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "P(x > 7) = P(8) + P(9) + P(10) + P(11) \n" ); document.write( "P(x > 7) = \n" ); document.write( "P(x >7) = .1774 + .0887 + .0266 + .0036 = .2963 \n" ); document.write( " |