document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913081>Question 913081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car leaves town traveling west at 45km/h. Three hours later another car leaves the same town traveling in the same direction at 60km/h. How far from town will the second car overtake the first car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554651 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gaining speed 60-45= 15 mph<BR>\n" );
document.write( "Head start 45*3 =135 miles<BR>\n" );
document.write( "Time to catch up 135/15=9 hours<BR>\n" );
document.write( "Algebraic solution<BR>\n" );
document.write( "45(t+3)=60t<BR>\n" );
document.write( "45t+135=60t<BR>\n" );
document.write( "135=60t-45t<BR>\n" );
document.write( "135=15t<BR>\n" );
document.write( "t=9 hours<BR>\n" );
document.write( "Distance to meeting 9*60=540 miles<BR>\n" );
document.write( "code drtch1<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );