document.write( "Question 913580: Find the vertex of each parabola and graph it.
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document.write( "1. y^2+4x-6y= -1
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document.write( "2. y=x^2+4x+5
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document.write( "3. y=-x^2-x+1 \n" );
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Algebra.Com's Answer #554627 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex of each parabola and graph it. \n" ); document.write( "Basic equation of parabola: \n" ); document.write( "1. y^2+4x-6y= -1 \n" ); document.write( "complete the square: \n" ); document.write( "(y^2-6y+9)+4x=-1+9 \n" ); document.write( "(y-3)^2=-4x+8 \n" ); document.write( "(y-3)^2=-4(x-2) \n" ); document.write( "Parabola opens left with vertex at(2,3) \n" ); document.write( ".. \n" ); document.write( "2. y=x^2+4x+5 \n" ); document.write( "complete the square: \n" ); document.write( "y=(x^2+4x+4)-4+5 \n" ); document.write( "(x+2)^2=(y-1) \n" ); document.write( "Parabola opens up with vertex at(-2,1) \n" ); document.write( ".. \n" ); document.write( "3. y=-x^2-x+1 \n" ); document.write( "complete the square: \n" ); document.write( "y=-(x^2+x+1/4)+1/4+1 \n" ); document.write( "(x+1/2)^2=-(y-5/4) \n" ); document.write( "Parabola opens down with vertex at(-1/2,5/4)\r \n" ); document.write( "\n" ); document.write( "Sorry, I don't have the means to graph these parabolas \n" ); document.write( " |