document.write( "Question 913580: Find the vertex of each parabola and graph it.
\n" ); document.write( "1. y^2+4x-6y= -1
\n" ); document.write( "2. y=x^2+4x+5
\n" ); document.write( "3. y=-x^2-x+1
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Algebra.Com's Answer #554627 by lwsshak3(11628)\"\" \"About 
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Find the vertex of each parabola and graph it.
\n" ); document.write( "Basic equation of parabola:
\n" ); document.write( "1. y^2+4x-6y= -1
\n" ); document.write( "complete the square:
\n" ); document.write( "(y^2-6y+9)+4x=-1+9
\n" ); document.write( "(y-3)^2=-4x+8
\n" ); document.write( "(y-3)^2=-4(x-2)
\n" ); document.write( "Parabola opens left with vertex at(2,3)
\n" ); document.write( "..
\n" ); document.write( "2. y=x^2+4x+5
\n" ); document.write( "complete the square:
\n" ); document.write( "y=(x^2+4x+4)-4+5
\n" ); document.write( "(x+2)^2=(y-1)
\n" ); document.write( "Parabola opens up with vertex at(-2,1)
\n" ); document.write( "..
\n" ); document.write( "3. y=-x^2-x+1
\n" ); document.write( "complete the square:
\n" ); document.write( "y=-(x^2+x+1/4)+1/4+1
\n" ); document.write( "(x+1/2)^2=-(y-5/4)
\n" ); document.write( "Parabola opens down with vertex at(-1/2,5/4)\r
\n" ); document.write( "\n" ); document.write( "Sorry, I don't have the means to graph these parabolas
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