document.write( "Question 913589: find the least value of n for which the sum of the first n odd natural numbers exceeds 5000.\r
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\n" ); document.write( "\n" ); document.write( "please give a very comprehensive answer easy to grasp.Thanks.
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Algebra.Com's Answer #554595 by mananth(16946)\"\" \"About 
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n odd numbers\r
\n" ); document.write( "\n" ); document.write( "1,3,5,7,9\r
\n" ); document.write( "\n" ); document.write( "Sum >5000\r
\n" ); document.write( "\n" ); document.write( "We will first find n for Sum = 5000\r
\n" ); document.write( "\n" ); document.write( "Sn = n/2(2a+(n-1)d)\r
\n" ); document.write( "\n" ); document.write( "a=1,d=2,Sn =5000\r
\n" ); document.write( "\n" ); document.write( "5000= n/2(2*1+(n-1)*2)\r
\n" ); document.write( "\n" ); document.write( "10000=n+(n-1)*2\r
\n" ); document.write( "\n" ); document.write( "10000=n+2n-2\r
\n" ); document.write( "\n" ); document.write( "10002=3n\r
\n" ); document.write( "\n" ); document.write( "n=3334\r
\n" ); document.write( "\n" ); document.write( "so for n =3334 Sum = 5000\r
\n" ); document.write( "\n" ); document.write( "SO for n=3335 Sum >5000\r
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