document.write( "Question 913425: how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of a 70% acid solution? \n" ); document.write( "
Algebra.Com's Answer #554515 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! how many liters of 80% acid solution must be mixed with 15% acid solution to get 455 L of a 70% acid solution? \n" ); document.write( "*** \n" ); document.write( "let x=amt of 80% solution to mix \n" ); document.write( "455-x=amt of 15% solution to mix \n" ); document.write( "80%x+15%(455-x)=70%*455 \n" ); document.write( ".80x+68.25-.15x=318.5 \n" ); document.write( "0.65x=250.25 \n" ); document.write( "x=385 \n" ); document.write( "455-x=70 \n" ); document.write( "amt of 80% solution to mix=385 liters \n" ); document.write( "amt of 15% solution to mix=70 liters \n" ); document.write( " |