document.write( "Question 77159: what value for x must be excluded in the following fraction?\r
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document.write( "x-3
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document.write( "over
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document.write( "(4x-5)(x+1)
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document.write( "am i right to say
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document.write( "5/4,1,3 \n" );
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Algebra.Com's Answer #55451 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "What values of x are not allowed? \n" ); document.write( ". \n" ); document.write( "The only thing that is not allowed in this expression is division by zero. Therefore, \n" ); document.write( "neither of the two terms in the denominator can equal zero. You can solve for values \n" ); document.write( "of x that are not allowed by setting each of the factors in the denominator equal to zero \n" ); document.write( "and then solving for the corresponding value of x. \n" ); document.write( ". \n" ); document.write( "So begin by saying: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Solve this by adding 5 to both sides to get \n" ); document.write( "of x ... 4 ... to get that \n" ); document.write( "if it did, then the factor \n" ); document.write( ". \n" ); document.write( "Next do the same type of calculation for the other factor in the denominator \n" ); document.write( "Set it equal to zero ... \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "if you let x = -1, the factor \n" ); document.write( "by zero which is not an allowable situation in algebra. This one you called +1 ... \n" ); document.write( "suggesting that you probably made a sign error somewhere. \n" ); document.write( ". \n" ); document.write( "As far as the numerator going to zero ... that is not a problem. So you can solve the \n" ); document.write( " \n" ); document.write( "the denominator are not zero when x = +3. There is no division by zero that occurs when \n" ); document.write( "x = 3 ... and when x = 3 the two factors in the denominator are: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( "is zero when x = 3, the expression becomes: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "In summary, the two non-allowed values are \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem a little more. \n" ); document.write( " |