document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77239>Question 77239</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle whose center is at the point (1,2) passes through the point (4,-2). What is the length of the radius of the circle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55443 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> center is at the point (1,2) ..say x1,y1<BR>\n" );
document.write( "passes through the point (4,-2).. say x2, y2 <BR>\n" );
document.write( "the length of the radius of the circle = distance between the points<BR>\n" );
document.write( "=sqrt [(x2-x1)^2+(y2-y1)^2]<BR>\n" );
document.write( "=sqrt[(4-1)^2+(-2-2)^2]<BR>\n" );
document.write( "=sqrt[(3^2)+(-4)^2<BR>\n" );
document.write( "=sqrt[(9)+(16)]<BR>\n" );
document.write( "=sqrt(25)<BR>\n" );
document.write( "=5\r<BR>\n" );
document.write( "\n" );
document.write( "The radius of the circle =5 units.<BR>\n" );
document.write( "okay<BR>\n" );
document.write( "good day </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );