document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77324>Question 77324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if f(x)=3sinx + 2cos2x, the value of (Pie/2) is  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55438 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The given function is: \r<BR>\n" );
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document.write( "f(x) = 3sinx + 2cos2x   \r<BR>\n" );
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document.write( "To find the value of f(pi/2) \r<BR>\n" );
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document.write( "Substituting for x, we get: \r<BR>\n" );
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document.write( "f(Pi/2) = 3 Sin (pi/2) + 2 Cos(2(pi/2))  -------------(1)\r<BR>\n" );
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document.write( "We know that the value of \r<BR>\n" );
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document.write( "Sin(pi/2) = 1 and cos (pi) = -1 \r<BR>\n" );
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document.write( "Hence, the equation becomes...\r<BR>\n" );
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document.write( "f(pi/2) = 3 (1) + 2 (-1)  \r<BR>\n" );
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document.write( "f(pi/2) = 3 - 2  \r<BR>\n" );
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document.write( "f(pi/2) = 1\r<BR>\n" );
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document.write( "Hence, the solution. </SPAN>\n" );
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