document.write( "Question 913201: The probability that a pen drawn at random from a box of pen is defective is 0.1. If a sample of 6 pens is taken, the probability of
\n" ); document.write( "1) no defective pens
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Algebra.Com's Answer #554371 by ewatrrr(24785)\"\" \"About 
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p = .1, n = 6
\n" ); document.write( "1) P(x = 0) = binompdf(6, .1, 0) 0r (.9)^6
\n" ); document.write( "2) P(x = 5 or 6 defective pens) = binompdf(6, .1, 5) + binompdf(6, .1, 6)
\n" ); document.write( "3) P(Less than 3 defective pens) = binomcdf(6, .1, 2)
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\n" ); document.write( "Or by hand Using
\n" ); document.write( "\"P+%28x%29=+highlight_green%28nCx%29%28p%5Ex%29%28q%29%5E%28n-x%29+\"
\n" ); document.write( "p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = .1 & q = .9 , n = 6
\n" ); document.write( "\"nCx+=+%28n%21%29%2Fx%21%28n+-+x%29%21%29\"
\n" ); document.write( "............For ex
\n" ); document.write( "3) P(Less than 3 defective pens) = P(0) + P(1)+ P(2) \r
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