document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913219>Question 913219</A>: <I><SPAN STYLE=\"word-break: break-all;\"> ABCD is parallelogram.AE and BE are angle bisector angle A and angle B . show that angle AEB is 90 degree </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554349 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AE bisects  angle A\r<BR>\n" );
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document.write( "let each bisected angle be x \r<BR>\n" );
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document.write( "angle A = 2x\r<BR>\n" );
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document.write( "Similarly let y be each of the bisected angle<BR>\n" );
document.write( "2y = angle B\r<BR>\n" );
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document.write( "2x+2y = 180 deg ( adjacent angles of a parallelogram)\r<BR>\n" );
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document.write( "x+y = 90\r<BR>\n" );
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document.write( "In triangle ABE\r<BR>\n" );
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document.write( "x +y + angle AEB = 180 deg. ( sum of angles of a triangle)\r<BR>\n" );
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document.write( "90+angle AEB = 180 deg<BR>\n" );
document.write( "angle AEB = 180-90<BR>\n" );
document.write( "Angle AEB = 90 deg </SPAN>\n" );
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