document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913146>Question 913146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A local specialty coffee shop wants to obtain 30 pounds of a mixture of coffee beans costing $4.40 per pound. They have a mixture costing $4.25 per pound and a mixture costing $4.50 per pound. How much of each should be used? (Use system of linear equations to solve the problem) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554336 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Coffee												<BR>\n" );
document.write( "	price	----------------			quantity							<BR>\n" );
document.write( "Mixture type I	4.25	----------------			x	pounds						<BR>\n" );
document.write( "Mixture Type II	4.50	------	30	-	x	pounds						<BR>\n" );
document.write( "Mixture	4.40	----------------	30									<BR>\n" );
document.write( "Total	30		pounds									<BR>\n" );
document.write( "4.25	x	+	4.5	(	30	-	x	)	=	132		<BR>\n" );
document.write( "4.25	x	+	135	-	4.5	x	=			132		<BR>\n" );
document.write( "4.25	x	-	4.5	x			=	132	-	135		<BR>\n" );
document.write( "-0.25	x			=	-3							<BR>\n" );
document.write( "/	-0.25											<BR>\n" );
document.write( "	x			=	12		pounds			$4.25		Mixture type I<BR>\n" );
document.write( "					18		pounds			$4.50		Mixture Type II<BR>\n" );
document.write( "												<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );