document.write( "Question 912967: two years ago , a father was five times old as his son . two years later from today his age will be 8 years more than three times the age of his son .find their present ages
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #554314 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
let f = father's present age
\n" ); document.write( "let s = son's age
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement, simplify as much as possible.
\n" ); document.write( ":
\n" ); document.write( "\" two years ago , a father was five times old as his son .\"
\n" ); document.write( "f - 2 = 5(s-2)
\n" ); document.write( "f - 2 = 5s - 10
\n" ); document.write( "f = 5s - 10 + 2
\n" ); document.write( "f = 5s - 8
\n" ); document.write( "\"two years later from today his age will be 8 years more than three times the age of his son \"
\n" ); document.write( "f + 2 = 3(s+2) + 8
\n" ); document.write( "f + 2 = 3s + 6 + 8
\n" ); document.write( "f = 3s + 14 - 2
\n" ); document.write( "f = 3s + 12
\n" ); document.write( "replace f with (5s-8), from the 1st statement
\n" ); document.write( "5s - 8 = 3s + 12
\n" ); document.write( "5s - 3s = 12 + 8
\n" ); document.write( "2s = 20
\n" ); document.write( "s = 10 yrs is the son's age
\n" ); document.write( "then
\n" ); document.write( "f = 5(10) - 8
\n" ); document.write( "f = 42 yrs is father's age
\n" ); document.write( ":
\n" ); document.write( "you can confirm this by putting these ages in both original statements and see if they are true.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );