document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913083>Question 913083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tim left Paris traveling 51 mph. Sally, to catch up, left sometime later driving 60 mph. Sally caught up after 4 hours. How long was Tim driving before Sally caught up?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554301 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Gaining speed 60 -51= 9 mph<BR>\n" );
document.write( "Time to catch up 4 hours<BR>\n" );
document.write( "Head start 9*4=36 miles\r<BR>\n" );
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document.write( "Algebraic solution<BR>\n" );
document.write( "9*4=36 miles head start<BR>\n" );
document.write( "60*4-51*4=9*4<BR>\n" );
document.write( "36 is less than 51 so he drove less than an hour\r<BR>\n" );
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document.write( "51t=36\r<BR>\n" );
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document.write( "t=36/51 0.71 hours or about 42.35 minutes\r<BR>\n" );
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