document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913054>Question 913054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of some rectangle is 35in^2. Four times the width of this rectangle is the same as 3 inches more than twice the length. What are the dimensions of the rectangle?\r<BR>\n" );
document.write( "\n" );
document.write( "I came up with the equations:<BR>\n" );
document.write( "4W=2L+3 and LxW=35<BR>\n" );
document.write( "I tried to do emilination, but because one of the equations is multiplying, it did not work. Should I substitute 4W=2L+3 with 4(35/L)=2L+3 and end up with a quadratic function & figure out the problem from there? Thank you so much for your time.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554271 by </B><A HREF=/tutors/aboutme.mpl?userid=ichigo449><B>ichigo449(30)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ichigo449><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Yes that works. To continue: 4(35/L) = 2L+3 or L/2 + 3/4 = 35/L or (L^2)/2 + 3L/4 - 35 = 0 which is solvable by quadratic formula. Have a nice day.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );