document.write( "Question 913039: A mother is 15 years older than twice her daughter's age. if the difference of their ages is 32, how old is each person? \n" ); document.write( "
Algebra.Com's Answer #554259 by josmiceli(19441)\"\" \"About 
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Let \"+m+%7D%7D%5D+=+mother%27s+age%0D%0ALet+%7B%7B%7B+d+\" = daughter's age
\n" ); document.write( "------------------------
\n" ); document.write( "(1) \"+m+=+2d+%2B+15+\"
\n" ); document.write( "(2) \"+m+=+d+%2B+32+\"
\n" ); document.write( "--------------------
\n" ); document.write( "By substitution:
\n" ); document.write( "(1) \"+d+%2B+32+=+2d+%2B+15+\"
\n" ); document.write( "(1) \"+d+=+32+-+15+\"
\n" ); document.write( "(1) \"+d+=+17+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+m+=+d+%2B+32+\"
\n" ); document.write( "(2) \"+m+=+49+\"
\n" ); document.write( "---------------
\n" ); document.write( "The mother is 49 and the daughter is 17
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+m+=+2d+%2B+15+\"
\n" ); document.write( "(1) \"+49+=+2%2A17+%2B+15+\"
\n" ); document.write( "(1) \"+49+=+34+%2B+15+\"
\n" ); document.write( "(1) \"+49+=+49+\"
\n" ); document.write( "OK
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