document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=913001>Question 913001</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm. more than twice the width. if the length of the rectangle is decreased by 2 cm and the width is decreased by 1 cm, the perimeter is 20cm. find the length and width of the original rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554254 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 1 cm. more than twice the width. if the length of the rectangle is decreased by 2 cm and the width is decreased by 1 cm, the perimeter is 20cm. find the length and width of the original rectangle?<BR>\n" );
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document.write( "let x=width of original triangle<BR>\n" );
document.write( "2x+1=length of original triangle<BR>\n" );
document.write( "2(width-length)=perimeter<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x-1=width of smaller triangle<BR>\n" );
document.write( "2x+1-2=2x-1=length of smaller triangle<BR>\n" );
document.write( "2(x-1+2x-1)=20<BR>\n" );
document.write( "2(3x-2)=20<BR>\n" );
document.write( "3x-2=10<BR>\n" );
document.write( "3x=12<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "2x+1=8+1=9<BR>\n" );
document.write( "width of original triangle=4 cm<BR>\n" );
document.write( "length of original triangle=9 cm </SPAN>\n" );
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