document.write( "Question 913016: Please help me solve this problem:
\n" ); document.write( "The supplement of an angle is 12 more than twice its compliment. Find the supplement of the complement of the angle. \n" ); document.write( "

Algebra.Com's Answer #554247 by MathLover1(20850) $\"\"$ $\"About$

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Complementary angles are angles that add up to $\"90\"$ degrees. \r
\n" ); document.write( "\n" ); document.write( "Supplementary angles are angles that add up to $\"180\"$ degrees. \r
\n" ); document.write( "\n" ); document.write( "let's angles be $\"alpha\"$ and $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha+%2B+beta=90\"$ => $\"alpha=90-beta\"$ and $\"alpha\"$ is a complement of $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha+%2B+beta=180\"$ => $\"alpha=180-beta\"$ and $\"alpha\"$ is a supplement of $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( "given: the supplement of an angle is $\"12\"$ more than $\"twice\"$ its compliment\r
\n" ); document.write( "\n" ); document.write( " $\"180-beta=2%2890-beta%29%2B12\"$ ...solve for $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"180-beta=180-2beta%2B12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2beta-beta=180-180%2B12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta=12\"$ \r
\n" ); document.write( "\n" ); document.write( "then, $\"alpha=180-beta\"$ => $\"alpha=180-12\"$ => $\"alpha=168\"$ -the supplement of angle $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=90-beta\"$ => $\"alpha=90-12\"$ => $\"alpha=78\"$ ............complement of angle $\"beta\"$
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