document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912949>Question 912949</A>: <I><SPAN STYLE=\"word-break: break-all;\"> complete the identity\r<BR>\n" );
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document.write( "-1+sec^2a<BR>\n" );
document.write( "---------- (over)<BR>\n" );
document.write( "Tana </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554204 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554204\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> complete the identity <BR>\n" );
document.write( "(-1+sec^2(a)) / Tan(a) = ?<BR>\n" );
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document.write( "Since sin^2 + cos^2 = 1<BR>\n" );
document.write( "Dividing by cos^2 you would get:<BR>\n" );
document.write( "tan^2 + 1 = sec^2<BR>\n" );
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document.write( "then 1-sec^2 = -tan^2<BR>\n" );
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document.write( "Your Problem::<BR>\n" );
document.write( "(-1+sec^2(a)) / Tan(a) = ?<BR>\n" );
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document.write( "-tan^2(a) / tan(a) = -1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( " </SPAN>\n" );
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