document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912874>Question 912874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father who was five times as old as his daughter 5 years ago is now three times as old as she is. Find their ages. I've really tried to solve this question. Help me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554133 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x daughter's age NOW. (father 3x )<BR>\n" );
document.write( "5years ago...<BR>\n" );
document.write( "3x - 5 = 5(x-5)<BR>\n" );
document.write( "20 = 2x<BR>\n" );
document.write( "10 = x, daughter's age NOW.  Father is 30<BR>\n" );
document.write( "And...checking...5years ago...<BR>\n" );
document.write( "25 = 5(5)<BR>\n" );
document.write( " </SPAN>\n" );
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