document.write( "Question 912875: Paul is twice as old as Becca. Five years ago the sum of their ages was 44. How old are they now?\r
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document.write( "How do I set this up to get my answer? \n" );
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Algebra.Com's Answer #554132 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! x Becca's age (Paul 2x) \n" ); document.write( "5 years ago... \n" ); document.write( "(2x-5) + (x-5) = 44 \n" ); document.write( "x = 54/3 = 18, Becca's age. Paul 36 \n" ); document.write( "And..checking \n" ); document.write( "13 + 31 = 44 \n" ); document.write( " \n" ); document.write( " |