document.write( "Question 912867: find the area of an isosceles right triangle whose one of the equal sides is 10 cm long. \n" ); document.write( "
Algebra.Com's Answer #554128 by ewatrrr(24785)\"\" \"About 
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isosceles right triangle: the sides are in the ratio 1:1: √2
\n" ); document.write( "When one of the equal sides is 10 ...b = 10√2 and (1/2)base = 5√2
\n" ); document.write( "h = sqrt(100 - 50) Pythagorean Theorem
\n" ); document.write( "h = 5√2
\n" ); document.write( "A = (1/2)bh = (1/2)(10√2)(5√2) = 50 cm^2
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