document.write( "Question 912860: Find the sum of four consecutive negative integers, such that the square of the sum of the first and fourth is 289. Thanks for your help. \n" ); document.write( "

Algebra.Com's Answer #554121 by ewatrrr(24785) $\"\"$ $\"About$

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four consecutive negative integers: x, x+1, x+2, x+3
\n" ); document.write( "(2x+3)^2 = 289
\n" ); document.write( "4x^2 + 12x + 9 = 289
\n" ); document.write( "4x^2 + 12x -280 = 0
\n" ); document.write( "x^2 + 3x -70 = 0
\n" ); document.write( "(x+10)(x-7) = 0
\n" ); document.write( "x = -10
\n" ); document.write( "The four consecutive negative integers are: -10, -9, -8, -7
\n" ); document.write( "Their sum = -34 \n" ); document.write( "

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