document.write( "Question 912852: An investment club invested a part of $14,000 in a 9% annual simple interest account and the remainder in a 15% annual simple interest account. The amount of interest earned for one year was $1800. How much was invested in the 9% account? \n" ); document.write( "

Algebra.Com's Answer #554118 by richwmiller(17219) $\"\"$ $\"About$

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Total amount of money invested: $14000
\n" ); document.write( "x+y=14000,
\n" ); document.write( "Total yearly interest for the two accounts is: $1800
\n" ); document.write( "0.09*x+0.15*y=1800
\n" ); document.write( "x=14000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.09*(14000-y)+0.15*y=1800
\n" ); document.write( "Multiply out
\n" ); document.write( "1260-0.09*y+0.15*y=1800
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.06*y=540
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 9000.00 at 15% earns $1350 interest
\n" ); document.write( "x=14000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 5000.00 at 9% earns $450 interest
\n" ); document.write( "Check
\n" ); document.write( "0.09*5000+0.15*9000=1800
\n" ); document.write( "450+1350=1800
\n" ); document.write( "1800=1800
\n" ); document.write( "If 1800=1800 is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "codeint1
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