document.write( "Question 77284This question is from textbook
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document.write( ": A rectangular painting has dimensions x and x + 10. The painting is in a frame 2 in. wide. The total area of the picture and the frame is 900 in. sq. What are the dimensions of the painting? \n" );
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Algebra.Com's Answer #55409 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! (x+4)(x+14)=900 \n" ); document.write( "x^2+18x+56-900=0 \n" ); document.write( "x^2+18x-844=0 \n" ); document.write( "using the quadratic equation we get \n" ); document.write( "X=(-18+-SQRT[18^2-4*1*-844])/2*1 \n" ); document.write( "X=(-18+-SQRT[324+3376])/2 \n" ); document.write( "X=(-18+-SQRT3700)/2 \n" ); document.write( "X=(-18+-60.828)/2 \n" ); document.write( "X=(-18+60.828)/2 \n" ); document.write( "X=42.828/2 \n" ); document.write( "X=21.414 & 21.414+10=31.414 ARE THE PICTURE DIMENSIONS \n" ); document.write( "PROOF \n" ); document.write( "(21.414+4)(21.414+14)=900 \n" ); document.write( "25.414*35.414=900 \n" ); document.write( "900=900 \n" ); document.write( " \n" ); document.write( " |