document.write( "Question 912739: Please help me solve this proof:\r
\n" ); document.write( "\n" ); document.write( "Prove that if a line is drawn through the vertex of an isosceles triangle parallel to the base, it bisects the exterior angle at the vertex.\r
\n" ); document.write( "\n" ); document.write( "I have drawn the picture as the question states, but am not sure how to prove that the line bisects the exterior angle with steps using a proof.
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Algebra.Com's Answer #554063 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let ABC be the triangle\r
\n" ); document.write( "\n" ); document.write( "AE is drawn parallel to BC\r
\n" ); document.write( "\n" ); document.write( "CAF is the external angle\r
\n" ); document.write( "\n" ); document.write( "To prove AE bisects CAF\r
\n" ); document.write( "\n" ); document.write( "AE is parallel to BC and AC is the transversal\r
\n" ); document.write( "\n" ); document.write( "So angle CAE = ACB ( alternate angle test)\r
\n" ); document.write( "\n" ); document.write( "AE is parallel to BC and Bf is the transversal
\n" ); document.write( "so EAF = ABC ( corresponding angles test)\r
\n" ); document.write( "\n" ); document.write( "But ABC = ACB ( isosceles triangle)\r
\n" ); document.write( "\n" ); document.write( "therefore EAF = CAE
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