document.write( "Question 912746: A car traveled a distance of 100 miles. If its average speed had been 8 mph more, the trip would have taken 25 minutes less. What was the car's average speed? Please show me the steps to solve this. \n" ); document.write( "
Algebra.Com's Answer #554047 by mananth(16946)\"\" \"About 
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A car traveled a distance of 100 miles. \r
\n" ); document.write( "\n" ); document.write( "let speed be x mph\r
\n" ); document.write( "\n" ); document.write( "If its average speed had been 8 mph more, (x+8) mph\r
\n" ); document.write( "\n" ); document.write( " the trip would have taken 25 minutes less. =25/60 = 5/12 hours\r
\n" ); document.write( "\n" ); document.write( "Time with original speed - time with increased speed = 5/12\r
\n" ); document.write( "\n" ); document.write( "t=d/r\r
\n" ); document.write( "\n" ); document.write( "\"%28100%2Fx%29+-+100%2F%28x%2B8%29+=+5%2F12\"\r
\n" ); document.write( "\n" ); document.write( "multiply equation by 12x(x+8)\r
\n" ); document.write( "\n" ); document.write( "12*100*(x+8) -12*100x = 5*x(x+8)\r
\n" ); document.write( "\n" ); document.write( "1200x+9600 -1200x = 5x^2+40x\r
\n" ); document.write( "\n" ); document.write( "5x^2+40x-9600=0\r
\n" ); document.write( "\n" ); document.write( "/5
\n" ); document.write( "x^2+8x-1920=0\r
\n" ); document.write( "\n" ); document.write( "x^2+8x+16 = 1920+16\r
\n" ); document.write( "\n" ); document.write( "(x+4)^2= 1936\r
\n" ); document.write( "\n" ); document.write( "x+4 = +/-44\r
\n" ); document.write( "\n" ); document.write( "ignore negative\r
\n" ); document.write( "\n" ); document.write( "x= 40 mph\r
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