document.write( "Question 912756: Cookie has 97 coins in her collection – all either nickels, dimes or quarters. If 77 of her coins are quarters and dimes and the total value of her coins is $13.95, how many quarters does she have?\r
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Algebra.Com's Answer #554031 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
– all either nickels, dimes or quarters. \r
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document.write( "n+d+q = 97\r\n" );
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\n" ); document.write( "If 77 of her coins are quarters and dimes
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document.write( "d+q=77\r\n" );
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\n" ); document.write( "And also that implies that the other 97-77 or 20 coins are nickels.
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document.write( "So n = 20\r\n" );
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\n" ); document.write( "the total value of her coins is $13.95
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document.write( "5n + 10d + 25q = 1395\r\n" );
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document.write( "So we have this system:\r\n" );
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document.write( "\"system%28n%2Bd%2Bq+=+97%2Cd%2Bq=77%2Cn=20%2C5n+%2B+10d+%2B+25q+=+1395%29\"\r\n" );
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document.write( "Substitute n=20\r\n" );
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document.write( "\"system%2820%2Bd%2Bq+=+97%2Cd%2Bq=77%2C20=20%2C5%2820%29+%2B+10d+%2B+25q+=+1395%29\"\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "\"system%28d%2Bq+=+77%2Cd%2Bq=77%2C100+%2B+10d+%2B+25q+=+1395%29\"\r\n" );
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document.write( "Simplify and delete duplicate equation:\r\n" );
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document.write( "\"system%28d%2Bq+=+77%2C10d+%2B+25q+=+1295%29\" \r\n" );
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document.write( "Solve that system and get d=42,q=35\r\n" );
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document.write( "Solution: 20 nickels, 42 dimes, 35 quarters.\r\n" );
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document.write( "Edwin

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