document.write( "Question 912772: factor complete : 7x^2 + 33x - 10 = 0 \n" ); document.write( "
Algebra.Com's Answer #554030 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Looking at the expression \"7x%5E2%2B33x-10\", we can see that the first coefficient is \"7\", the second coefficient is \"33\", and the last term is \"-10\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"7\" by the last term \"-10\" to get \"%287%29%28-10%29=-70\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-70\" (the previous product) and add to the second coefficient \"33\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-70\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-70\":\r
\n" ); document.write( "\n" ); document.write( "1,2,5,7,10,14,35,70\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-5,-7,-10,-14,-35,-70\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-70\".\r
\n" ); document.write( "\n" ); document.write( "1*(-70) = -70
\n" ); document.write( "2*(-35) = -70
\n" ); document.write( "5*(-14) = -70
\n" ); document.write( "7*(-10) = -70
\n" ); document.write( "(-1)*(70) = -70
\n" ); document.write( "(-2)*(35) = -70
\n" ); document.write( "(-5)*(14) = -70
\n" ); document.write( "(-7)*(10) = -70\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"33\":\r
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First NumberSecond NumberSum
1-701+(-70)=-69
2-352+(-35)=-33
5-145+(-14)=-9
7-107+(-10)=-3
-170-1+70=69
-235-2+35=33
-514-5+14=9
-710-7+10=3
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-2\" and \"35\" add to \"33\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-2\" and \"35\" both multiply to \"-70\" and add to \"33\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"33x\" with \"-2x%2B35x\". Remember, \"-2\" and \"35\" add to \"33\". So this shows us that \"-2x%2B35x=33x\".\r
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\n" ); document.write( "\n" ); document.write( "\"7x%5E2%2Bhighlight%28-2x%2B35x%29-10\" Replace the second term \"33x\" with \"-2x%2B35x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%287x%5E2-2x%29%2B%2835x-10%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%287x-2%29%2B%2835x-10%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%287x-2%29%2B5%287x-2%29\" Factor out \"5\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%287x-2%29\" Combine like terms. Or factor out the common term \"7x-2\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"7x%5E2%2B33x-10\" factors to \"%28x%2B5%29%287x-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"7x%5E2%2B33x-10=%28x%2B5%29%287x-2%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x%2B5%29%287x-2%29\" to get \"7x%5E2%2B33x-10\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "\n" ); document.write( "Let me know if you need more help or if you need me to explain a step in more detail.
\n" ); document.write( "Feel free to email me at jim_thompson5910@hotmail.com
\n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r
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\n" ); document.write( "\n" ); document.write( "Thanks,\r
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\n" ); document.write( "\n" ); document.write( "Jim
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