document.write( "Question 912759: A barge on the Sacramento River travels 24 miles upstream in 3 hours. The return trip takes the barge only two hours. Find the rate of the barge in still water.\r
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Algebra.Com's Answer #554020 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
r*t=d
\n" ); document.write( "with the current
\n" ); document.write( "(r+c)*2=24
\n" ); document.write( "(r+c)=24/2
\n" ); document.write( "r+c=12
\n" ); document.write( "against the current
\n" ); document.write( "(r-c)*3=24
\n" ); document.write( "(r-c)=24/3\r
\n" ); document.write( "\n" ); document.write( "r-c=8
\n" ); document.write( "r+c=12
\n" ); document.write( "add
\n" ); document.write( "r+r=12+8
\n" ); document.write( "2r=20
\n" ); document.write( "r=10 mph rate still water\r
\n" ); document.write( "\n" ); document.write( "10-c=8
\n" ); document.write( "c=10-8
\n" ); document.write( "c=2 mph current
\n" ); document.write( "check
\n" ); document.write( "(10+2)*2=24
\n" ); document.write( "12*2=24
\n" ); document.write( "24=24
\n" ); document.write( "ok
\n" ); document.write( "(r-c)*3=24
\n" ); document.write( "(10-2)*3=24
\n" ); document.write( "8*3=24
\n" ); document.write( "24=24
\n" ); document.write( "ok
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