document.write( "Question 912742: Gertrude rows her boat 24 miles downstream in 4 hours. In order to make the return trip upstream in the same amount of time, the rate of the boat in still water was doubled. Find the rate of the current and the rate that Gertrude was rowing downstream.\r
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document.write( "Can you please hell me. I don't understand this problem. \n" );
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Algebra.Com's Answer #554006 by josgarithmetic(39631) ![]() You can put this solution on YOUR website! Uniform Rates for Travel, RT=D rate time distance\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let r be the rate Gertrude would row if no river current \n" ); document.write( "Let c be the rate of the river, the rate of flow of the river current\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "_________________rate________time__________distance \n" ); document.write( "DOWNSTREAM_______r+c____________4_____________24 \n" ); document.write( "UPSTREAM_________2r-c___________4_____________24\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Note very carefully, \"the rate of the boat in still water was doubled\".\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Downstream Equation: \n" ); document.write( "Simplify: \n" ); document.write( "Upstream Equation: \n" ); document.write( "Simplify: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve this system for r and c: \n" ); document.write( " |