document.write( "Question 912741: A total of $35,000 is invested into two banks accounts paying 6% and 4% simple interest. The yearly interest is $1710. How much is invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #554004 by mananth(16946)\"\" \"About 
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Part I 6.00% per annum ---x
\n" ); document.write( "Part II 4.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 35000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "6.00% x + 4.00% y= 1710
\n" ); document.write( "Multiply by 100
\n" ); document.write( "6 x + 4 y= 171000.00 --------2
\n" ); document.write( "Multiply (1) by -6
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y= -210000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x -2 y= -39000
\n" ); document.write( "divide by -2
\n" ); document.write( " y = 19500
\n" ); document.write( "Part I 6.00% $ 15500
\n" ); document.write( "Part II 4.00% $ 19500
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\n" ); document.write( "CHECK
\n" ); document.write( "15500 --------- 6.00% ------- 930.00
\n" ); document.write( "19500 ------------- 4.00% ------- 780.00
\n" ); document.write( "Total -------------------- 1710.00
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\n" ); document.write( "m.ananth@hotmail.ca
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