document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912723>Question 912723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 8 am , Madge leaves home on a business trip traveling an incredible 35 mph. A half hour later, Dorkus discovers that Madge forgot her briefcase. Unable to operate a cell phone, he hopes on his Harley and guns it, only to realized he forgot the briefcase as well. Finally , 15 minutes after he realized she left without the case, he zooms down the highway at a reckless 59 mph. When will he catch up with Madge? ( provided he knows which way she went, which may not be a good assumption to make ...) \r<BR>\n" );
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document.write( "Can you please help me solve this problem. I got very confuse when I was reading it and I didn't know where to even start.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #554002 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=554002\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Madge speed = 35 mph\r<BR>\n" );
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document.write( "In half hour she travels 17.5 miles<BR>\n" );
document.write( "In 3/4 hours she is 26.25 miles away\r<BR>\n" );
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document.write( "difference in their speeds = 59-35 = 24 mph\r<BR>\n" );
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document.write( "I presume the time is 3/4 hour when he starts to catch up\r<BR>\n" );
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document.write( "she would be 26.25 miles away\r<BR>\n" );
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document.write( "catch up time = 26.25/24<BR>\n" );
document.write( "=1.09 \r<BR>\n" );
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document.write( "0.09*60= 5.4 minutes\r<BR>\n" );
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document.write( "He catches up at 9.06 am.\r<BR>\n" );
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