document.write( "Question 909983: compute the area between y=|x| and y=x^2-6 \n" ); document.write( "
Algebra.Com's Answer #554000 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "First make sure that all possible vertical line segments drawn from\r\n" );
document.write( "the upper boundary of area to lower boundary are such that they all\r\n" );
document.write( "begin on one curve and end on the other.  If so, then\r\n" );
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document.write( "Area between two curves = \r\n" );
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document.write( "We draw the graph of the two curves:\r\n" );
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document.write( "y=|x| is really this piece-wise function:\r\n" );
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document.write( "We find the point of intersection:\r\n" );
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document.write( "\"system%28y=x%5E2-6%2Cy=x%29\"\r\n" );
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document.write( "\"x%5E2-6=x\"\r\n" );
document.write( "\"x%5E2-x-6=0\"\r\n" );
document.write( "\"%28x-3%29%28x%2B2%29=0\"\r\n" );
document.write( "x-3=-0   x+2=0\r\n" );
document.write( "  x=3      \"cross%28x=-2%29\"\r\n" );
document.write( "y=x       (not pertinent)\r\n" );
document.write( "y=3\r\n" );
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document.write( "The point of intersection is (3,3)\r\n" );
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document.write( "By symmetry we can find the area of the right half\r\n" );
document.write( "from x=0 to x=3 and then double it.\r\n" );
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document.write( "\"Area\"\"%22%22=%22%22\"\"2%2Aint%28++%28x%29-%28x%5E2-6%29%2Cdx%2C0%2C3%29\"\"%22%22=%22%22\"\"2%2Aint%28++%28x-x%5E2%2B6%29%2Cdx%2C0%2C3%29\"\"%22%22=%22%22\"\"%22%22=%22%22\"\r\n" );
document.write( "\"%22%22=%22%22\"\"%22%22=%22%22\"\"2%2A%28expr%281%2F2%293%5E2-expr%281%2F3%293%5E3%2B6%2A3%29-0\"\"%22%22=%22%22\"\r\n" );
document.write( "\"2%2A%28expr%281%2F2%299-expr%281%2F3%2927%2B18%29\"\"%22%22=%22%22\"\"2%2A%289%2F2-9%2B18%29\"\"%22%22=%22%22\"\"2%2A%289%2F2%2B9%29\"\"%22%22=%22%22\"\"9%2B18\"\"%22%22=%22%22\"\"27\"\r\n" );
document.write( " \r\n" );
document.write( "Edwin
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