document.write( "Question 912736: Joe wants to invest $30,000. He puts part of his money in company x with 0.4% interest return and part of his money in company y with 6% return. At the end of the year he received $1500 in interest. How much money did he invest in each company? \n" ); document.write( "
Algebra.Com's Answer #553997 by richwmiller(17219)\"\" \"About 
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I will assume you really mean 4% and 6% other wise you earn about $21 at .4%\r
\n" ); document.write( "\n" ); document.write( "Total amount of money invested: $30000
\n" ); document.write( "x+y=30000,
\n" ); document.write( "Total yearly interest for the two accounts is: $1500
\n" ); document.write( "0.04*x+0.06*y=1500
\n" ); document.write( "x=30000-y
\n" ); document.write( "Substitute for x
\n" ); document.write( "0.04*(30000-y)+0.06*y=1500
\n" ); document.write( "Multiply out
\n" ); document.write( "1200-0.04*y+0.06*y=1500
\n" ); document.write( "Combine like terms.
\n" ); document.write( "0.02*y=300
\n" ); document.write( "Isolate y
\n" ); document.write( "y=$ 15000.00 at 6% earns $900 interest
\n" ); document.write( "x=30000-y
\n" ); document.write( "Calculate x
\n" ); document.write( "x=$ 15000.00 at 4% earns $600 interest
\n" ); document.write( "Check
\n" ); document.write( "0.04*15000+0.06*15000=1500
\n" ); document.write( "600+900=1500
\n" ); document.write( "1500=1500
\n" ); document.write( "If 1500=1500 is TRUE and neither x nor y is negative then all is well
\n" ); document.write( "codeint1\r
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