document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912664>Question 912664</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 106 cm. If the length is 7 cm less than three times the width, what are the dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553996 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553996\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> perimeter = 2length + 2width<BR>\n" );
document.write( "106 = 2(3w-7) + 2w<BR>\n" );
document.write( "106 = 6w-14 +2w<BR>\n" );
document.write( "106 = 8w-14<BR>\n" );
document.write( "120 = 8w<BR>\n" );
document.write( "15 = w<BR>\n" );
document.write( "l = 3*15 - 7<BR>\n" );
document.write( "l = 45-7<BR>\n" );
document.write( "l = 38<BR>\n" );
document.write( "106 = 38 + 38 + 15 + 15<BR>\n" );
document.write( "106 = 76 + 30<BR>\n" );
document.write( "106 = 106 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );