document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77304>Question 77304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the following word problem.\r<BR>\n" );
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document.write( "The hypotenuse of a right triangle is four feet longer than three times the shorter leg.  The longer leg is one foot less than the hypotenuse.  Find the dimensions of the right triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55398 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> HYP=(3X+4) X BEING THE SHORTEST LEG1.<BR>\n" );
document.write( "LONGER LEG2=(3X+4)-1<BR>\n" );
document.write( "THUS THE HYP^2=(LEG1)^2+(LEG*2)^2<BR>\n" );
document.write( "(3X+4)^2=X^2+(3X+4-1)^2<BR>\n" );
document.write( "9X^2+24X+16=X^2+(3X+3)^2<BR>\n" );
document.write( "9X^2+24X+16=X^2+9X^2+18X+9 WE CAN CANCEL OUT THE 9X^2 TERMS & WE HAVE LEFT<BR>\n" );
document.write( "24X-X^2-18X+16-9=0<BR>\n" );
document.write( "-X^2+6X+7=0<BR>\n" );
document.write( "X^2-6X-7=0<BR>\n" );
document.write( "(X-7)(X+1)=0<BR>\n" );
document.write( "X-7=0<BR>\n" );
document.write( "X=7 ANSWER.<BR>\n" );
document.write( "HYP=3*7+4<BR>\n" );
document.write( "HYP=21+4<BR>\n" );
document.write( "HYP=25 ANSWER.<BR>\n" );
document.write( "LONG SIDE=(3*7+3)<BR>\n" );
document.write( "LONG SIDE=24 ANSWER.<BR>\n" );
document.write( "SHORT SIDE=7 ANSWER.<BR>\n" );
document.write( "25^2=24^2+7^2<BR>\n" );
document.write( "625=576+49<BR>\n" );
document.write( "625=625 </SPAN>\n" );
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