document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912561>Question 912561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Four times a first number decreased by a second number is 20. The first number increased by three times the second number is 31. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553901 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(4x - y = 20)<BR>\n" );
document.write( "<u>x + 3y = 31</u><BR>\n" );
document.write( "13x = 91<BR>\n" );
document.write( "x = 7 and y = 8  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%2A7+-+y+=+20 ALIGN=MIDDLE  ALT=\"4%2A7+-+y+=+20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And...checking<BR>\n" );
document.write( "7 + 24 = 31 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );