document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=912535>Question 912535</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On a drive to Hopkinsville you take the scenic route and drive at average 50 mph. On your return, you take a road that is 10 miles longer, but since you can drive at average speed 60 mph, it takes you 2 minutes shorter than the trip to Hopkinsville. How far is Hopkinsville from your starting point? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #553859 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=553859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D Distance Hopkinsville is from starting point <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28D%2B10%29%2F60+-+D%2F50+=+%281%2F30%29+hr ALIGN=MIDDLE  ALT=\"%28D%2B10%29%2F60+-+D%2F50+=+%281%2F30%29+hr\"   DISABLED_style= \"max-width:90%; height:auto;\" >|Multiplying thru by 300 so as all denominators = 1<BR>\n" );
document.write( "50(D+10) - 60D = 10<BR>\n" );
document.write( "50d + 500 - 60D = 10<BR>\n" );
document.write( "490 = 10D<BR>\n" );
document.write( "49MI = D, Distance Hopkinsville is from starting point  </SPAN>\n" );
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