document.write( "Question 77295: can someone explain to me how to solve this please?\r
\n" ); document.write( "\n" ); document.write( "x/3-1/4=3x-8/12
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Algebra.Com's Answer #55385 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"x%2F3-1%2F4=3x-8%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3=3x-8%2F12%2B1%2F4\" Add 1/4 to both sides\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3-3x=-8%2F12%2B1%2F4\" Subtract 3x from both sides\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3-%283%2F3%293x=-8%2F12%2B%283%2F3%29%281%2F4%29\" Multiply the last terms on both sides by (3/3)\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3-%289%2F3%29x=-8%2F12%2B3%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-9x%29%2F3=%28-8%2B3%29%2F12\" Combine the fractions\r
\n" ); document.write( "\n" ); document.write( "\"%28-8x%29%2F3=%28-5%29%2F12\"\r
\n" ); document.write( "\n" ); document.write( "\"%28-8x%29=%283%29%28%28-5%29%2F12%29\" Multiply both sides by 3\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-15%2F12%29%2F%28-8%29\" Divide both sides by -8\r
\n" ); document.write( "\n" ); document.write( "\"x=%28-15%2F12%29%2A%28-1%2F8%29\" Multiply the reciprocal \r
\n" ); document.write( "\n" ); document.write( "\"x=15%2F96\" So this is the answer
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