document.write( "Question 912042: in how many ways can 9 people petitioned into committees containing 4,3 and 2 members respectively?
\n" ); document.write( "a- 9!/9!3!2!
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\n" ); document.write( "c- 9! 4! 3! 2!
\n" ); document.write( "d- 4! 3! 2!
\n" ); document.write( "e- 3. 4!3!2! \n" ); document.write( "

Algebra.Com's Answer #553802 by Edwin McCravy(20054) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "We choose the 4 in 9C4 ways.  That's \r\n" );
document.write( "We choose the 3 in 5C3 ways.  That's \r\n" );
document.write( "We choose the 2 in 2C2 ways.  That's \r\n" );
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document.write( "Multiplying all those together, that's\r\n" );
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document.write( "That's \r\n" );
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document.write( "That's not listed, but I'm guessing choice c was supposed to be 9!/(4!3!2!).\r\n" );
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document.write( "Edwin

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